S2T2

Jim Randell 9:33 am on 15 June 2023 Permalink Reply
Tags: by: Victor Bryant ( 142 )   

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  Jim Randell 9:33 am on 15 June 2023 Permalink | Reply

  I supposed the numbers were from 1 to 99 (although you can also use 0 if you like).

  This Python program combines the [[ int2words() ]] and [[ filter_unique() ]] functions from the enigma.py library.

  It runs in 58ms. (Internal runtime is 267µs).

  Run: [ @replit ]

  from enigma import (irange, int2words, filter_unique, intersect, join, printf)
  
  # numbers from 1 to 99 as words
  ns = dict((n, int2words(n)) for n in irange(1, 99))
  
  # return a function to select letters at indices <js> from the spelling of a number
  select = lambda *js: (lambda k: join(ns[k][j] for j in js))
  
  # the number is ambiguous by first letter
  ss1 = filter_unique(ns.keys(), f=select(0)).non_unique
  
  # but unique by first + last letter
  ss2 = filter_unique(ns.keys(), f=select(0, -1)).unique
  
  # from these it is unique by last letter
  ss = filter_unique(intersect([ss1, ss2]), f=select(-1)).unique
  
  # output solution
  printf("{ss}", ss=join(ss, sep=", "))
  

  Solution: The number is 98.

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  Frits 2:06 pm on 15 June 2023 Permalink | Reply

  Maintaining a dictionary.

     
  from enigma import int2words
  
  # lowercase letters
  letters = ''.join(chr(ord('a') + i) for i in range(26))
   
  # numbers from 1 to 99 as words
  nums = [int2words(n) for n in range(1, 100)]
  
  # the number is ambiguous by first letter
  d = {l: [x for x in nums if x[0] == l] for l in letters}
  d = {k: vs for k, vs in d.items() if len(vs) > 1}
  
  # but unique by first + last letter
  d = {l1 + l2: [x for x in nums if x[0] == l1 and x[-1] == l2 and x[0] in d] 
                 for l1 in letters for l2 in letters}
  d = {k: vs for k, vs in d.items() if len(vs) == 1}       
  
  # from these it is unique by last letter
  d = {k[-1]: [vs2 for k2, vs2 in d.items() if k[-1] == k2[-1]] for k in d}   
  d = {k: vs for k, vs in d.items() if len(vs) == 1}
  
  for k, v in d.items():
    print("answer:", *v[0])
  

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