## Teaser 2952: Silly slip

**From The Sunday Times, 21st April 2019** [link]

Please help me find my silly slip. I correctly added a five-figure number to a four-figure number to give a six-figure total. Then I tried to substitute letters for digits systematically and I ended up with:

SILLY + SLIP = PLEASEHowever, in these letters I have made one silly slip, so please find it and then work out what the correct sum was.

What was the correct six-figure numerical answer?

[teaser2952]

## Jim Randell 8:58 am

on16 April 2019 Permalink |We can use the [[

`bungled_sum()`

]] solver (originally written forPuzzle 56).Run:[ @repl.it ]Solution:The numerical result of the sum is 106496.The mistake is in the L of PLEASE (the result of the sum), it should be a letter that is different from all the other letters, although that does make it hard to make an acceptable word, but we can check this makes a viable alphametic sum using the [[

`SubstitutedSum()`

]] solver from theenigma.pylibrary.LikeLike

## Jim Randell 4:06 pm

on20 April 2019 Permalink |I assumed this puzzle was in the same vein as other “bungled sum” problems.

But the text says that letters are substituted for digits “systematically”, but it doesn’t say that each letter stands for a different digit (which is usual in alphametic puzzles).

If we allow letters to stand for the same digit, then we

cansolve the alphametic sum:The duplicated digits are: A and L are both 0, I and S are both 9.

LikeLike

## Jim Randell 11:01 pm

on21 April 2019 Permalink |Here is a faster (but longer) solution, using the

minizinc.pylibrary.LikeLike